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I 1 5 20
II 3 5 4
III 5 5 20
X = [ (1)(20) + (3)(4) + (5)(5) ] : (20+4+20)
= 132/44
= 3
Y = [ (5)(20) + (5)(4) + (5)(20) ] : (20+4+20)
= 220/44
= 5
Titik berat ( 3;5 )