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m = Δy / Δx
m = -2/4
m= -1/2
sejajar, maka gradien sama
garis b melalui titik (0, -3)
x1 = 0
y1 = -3
persamaan garis b
y - y1 = m(x - x1)
y - (-3) = -1/2(x - 0)
--------------------------- kedua ruas dikali 2
2(y + 3) = -x
2y + 6 = -x
x + 2y + 6 = 0
Jawaban D