Question

Х b) f(x) = f(x) = 5 - +3 Х 2 у -2 -1 о 1 2. у 3 2 -1 10
alguien que me ayudeeee​

Answer 1

【Rpta.】La gráfica se encuentra en la imagen.

                                 [tex]\green{{\hspace{50 pt}\above 1.2pt}\boldsymbol{\mathsf{Procedimiento}}{\hspace{50pt}\above 1.2pt}}[/tex]

Para poder graficar la función reemplazaremos los valores de x en f(x)

      [tex]\begin{array}{c}\sf{\boldsymbol{\bigcirc\kern-8pt\triangleright}\:\:Cuando\ \blue{x = -2}}\\\\\sf{y=\dfrac{x}{2} + 3}\\\\\sf{y=\dfrac{-2}{2} + 3}\\\\\sf{y=-1 + 3}\\\\\boxed{\sf{y=2}}\end{array}[/tex]              [tex]\begin{array}{c}\sf{\boldsymbol{\bigcirc\kern-8pt\triangleright}\:\:Cuando\ \blue{x = -2}}\\\\\sf{y=\dfrac{x}{2} + 3}\\\\\sf{y=\dfrac{-1}{2} + 3}\\\\\sf{y=-0.5 + 3}\\\\\boxed{\sf{y=2.5}}\end{array}[/tex]            [tex]\begin{array}{c}\sf{\boldsymbol{\bigcirc\kern-8pt\triangleright}\:\:Cuando\ \blue{x = -2}}\\\\\sf{y=\dfrac{x}{2} + 3}\\\\\sf{y=\dfrac{0}{2} + 3}\\\\\sf{y=0 + 3}\\\\\boxed{\sf{y=3}}\end{array}[/tex]

                         [tex]\begin{array}{c}\sf{\boldsymbol{\bigcirc\kern-8pt\triangleright}\:\:Cuando\ \blue{x = -2}}\\\\\sf{y=\dfrac{x}{2} + 3}\\\\\sf{y=\dfrac{1}{2} + 3}\\\\\sf{y=0.5 + 3}\\\\\boxed{\sf{y=3.5}}\end{array}[/tex]                [tex]\begin{array}{c}\sf{\boldsymbol{\bigcirc\kern-8pt\triangleright}\:\:Cuando\ \blue{x = -2}}\\\\\sf{y=\dfrac{x}{2} + 3}\\\\\sf{y=\dfrac{2}{2} + 3}\\\\\sf{y=1 + 3}\\\\\boxed{\sf{y=4}}\end{array}[/tex]

Ordenamos los valores en una tabla

                                                        [tex]\begin{array}{c|c}\blue{\sf{x}}&\blue{\sf{y}}\\^{\rule{50 pt}{0.4pt}\hspace{-30pt}}\\\sf{-2}&\sf{2}\\\sf{-1}&\sf{2.5}\\\sf{0}&\sf{3}\\\sf{1}&\sf{3.5}\\\sf{2}&\sf{4}\\\end{array}[/tex]

Procedemos a graficar nuestros resultados en un plano cartesiano(ver imagen).

                                               [tex]\boxed{\sf{{R}}\quad\raisebox{10pt}{$\sf{\red{O}}$}\!\!\!\!\raisebox{-10pt}{$\sf{\red{O}}$}\quad\raisebox{15pt}{$\sf{{G}}$}\!\!\!\!\raisebox{-15pt}{$\sf{{G}}$}\quad\raisebox{15pt}{$\sf{\red{H}}$}\!\!\!\!\raisebox{-15pt}{$\sf{\red{H}}$}\quad\raisebox{10pt}{$\sf{{E}}$}\!\!\!\!\raisebox{-10pt}{$\sf{{E}}$}\quad\sf{\red{R}}}\hspace{-64.5pt}\rule{10pt}{.2ex}\:\rule{3pt}{1ex}\rule{3pt}{1.5ex}\rule{3pt}{2ex}\rule{3pt}{1.5ex}\rule{3pt}{1ex}\:\rule{10pt}{.2ex}[/tex]

Answer 2

Respuesta:

no es 9

Explicación paso a paso: