Respuesta:
[tex]=\left(b-2\right)\left(b-5\right)[/tex]
Explicación paso a paso:
[tex]b^2-7b+10[/tex]
[tex]=\left(b^2-2b\right)+\left(-5b+10\right)[/tex]
[tex]=b\left(b-2\right)-5\left(b-2\right)[/tex]
dame corona xfa
espero haberte ayudado xd
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Verified answer
Respuesta:
[tex]=\left(b-2\right)\left(b-5\right)[/tex]
Explicación paso a paso:
[tex]b^2-7b+10[/tex]
[tex]=\left(b^2-2b\right)+\left(-5b+10\right)[/tex]
[tex]=b\left(b-2\right)-5\left(b-2\right)[/tex]
[tex]=\left(b-2\right)\left(b-5\right)[/tex]
dame corona xfa
espero haberte ayudado xd