Odpowiedź:
m=5 g; V=4 l=0,004 m^3
T1=273+20=293 K
T2= 273+40=313
M=28 g/mol azot
R=8,314 J/molK
---------------------------
n=5/28
p1= 5*8,314*293/(28*0,004)=108 750 Pa
p/T=const dla V=const
p2=p1*T2/T1= 108750*313/293=116173 Pa
Wyjaśnienie:
wzory:
p=nRT/V [Pa]
n=m/M ilość moli
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Odpowiedź:
m=5 g; V=4 l=0,004 m^3
T1=273+20=293 K
T2= 273+40=313
M=28 g/mol azot
R=8,314 J/molK
---------------------------
n=5/28
p1= 5*8,314*293/(28*0,004)=108 750 Pa
p/T=const dla V=const
p2=p1*T2/T1= 108750*313/293=116173 Pa
Wyjaśnienie:
wzory:
p=nRT/V [Pa]
n=m/M ilość moli