Respuesta:
Explicación paso a paso:
[tex]Diagonal: l =?[/tex]
[tex]l = \sqrt{(40cm)^{2}+(20cm)^{2} +(20cm)^{2} }[/tex]
[tex]l= \sqrt{1600cm^{2}+400cm^{2} +400cm^{2} }[/tex]
[tex]l = \sqrt{2400cm^{2} } = \sqrt{(4*6*100)cm^{2} }[/tex]
[tex]l= 2*10*\sqrt{6} cm[/tex]
[tex]l = 20\sqrt{6} cm[/tex]
[tex]l = 48.99cm[/tex]
Es un número irracional.
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[tex]Diagonal : l =?[/tex]
[tex]l= \sqrt{(10cm)^{2}+(10cm)^{2} +(10cm)^{2} }[/tex]
[tex]l= \sqrt{100cm^{2}+100cm^{2} +100cm^{2} }[/tex]
[tex]l = \sqrt{300cm^{2} } = \sqrt{100* 3 cm^{2} }[/tex]
[tex]l = 10\sqrt{3} cm[/tex]
[tex]l= 17.32cm[/tex]
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Respuesta:
Explicación paso a paso:
[tex]Diagonal: l =?[/tex]
[tex]l = \sqrt{(40cm)^{2}+(20cm)^{2} +(20cm)^{2} }[/tex]
[tex]l= \sqrt{1600cm^{2}+400cm^{2} +400cm^{2} }[/tex]
[tex]l = \sqrt{2400cm^{2} } = \sqrt{(4*6*100)cm^{2} }[/tex]
[tex]l= 2*10*\sqrt{6} cm[/tex]
[tex]l = 20\sqrt{6} cm[/tex]
[tex]l = 48.99cm[/tex]
Es un número irracional.
--------------------------------------------------------------------------------------------------
[tex]Diagonal : l =?[/tex]
[tex]l= \sqrt{(10cm)^{2}+(10cm)^{2} +(10cm)^{2} }[/tex]
[tex]l= \sqrt{100cm^{2}+100cm^{2} +100cm^{2} }[/tex]
[tex]l = \sqrt{300cm^{2} } = \sqrt{100* 3 cm^{2} }[/tex]
[tex]l = 10\sqrt{3} cm[/tex]
[tex]l= 17.32cm[/tex]
Es un número irracional.