Respuesta:
x= -1/3 ; y =28/21
Explicación paso a paso:
5x + 2y = 1 .....(I)
-3x + 3y = 5...(II)
5x + 2y = 1
5x = 1 - 2y
x = [tex]\frac{1 - 2y}{5}[/tex]
-3([tex]\frac{1-2y}{5}[/tex]) + 3y = 5
[tex]\frac{-3 + 6y}{5}[/tex] + 3y = 5
[tex]\frac{-3 + 6y}{5}[/tex] = 5 - 3y
-3 + 6y = 5(5 - 3y)
-3 + 6y = 25 - 15y
6y + 15y = 25 + 3
21y = 28
x =[tex]\frac{1-2y}{5}[/tex]
x= [tex]\frac{1-2(\frac{28}{21})}{5}[/tex]
x =[tex]\frac{1 - \frac{56}{21} }{5}[/tex]
x = [tex]\frac{\frac{-5}{3} }{5}[/tex]
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Respuesta:
x= -1/3 ; y =28/21
Explicación paso a paso:
⇒ Por método de sustitución:
5x + 2y = 1 .....(I)
-3x + 3y = 5...(II)
→ Despejando "x" en (I):
5x + 2y = 1
5x = 1 - 2y
x = [tex]\frac{1 - 2y}{5}[/tex]
→ Reemplazando en (II):
-3([tex]\frac{1-2y}{5}[/tex]) + 3y = 5
[tex]\frac{-3 + 6y}{5}[/tex] + 3y = 5
[tex]\frac{-3 + 6y}{5}[/tex] = 5 - 3y
-3 + 6y = 5(5 - 3y)
-3 + 6y = 25 - 15y
6y + 15y = 25 + 3
21y = 28
y = [tex]\frac{28}{21}[/tex]
⇒ Para hallar "x":
x =[tex]\frac{1-2y}{5}[/tex]
x= [tex]\frac{1-2(\frac{28}{21})}{5}[/tex]
x =[tex]\frac{1 - \frac{56}{21} }{5}[/tex]
x = [tex]\frac{\frac{-5}{3} }{5}[/tex]
x = [tex]\frac{-1}{3}[/tex]