Respuesta:
d = 6 cm At = 226,2 [tex]cm^{2}[/tex]
Explicación paso a paso:
v = 423,9 [tex]cm^{3}[/tex]
[tex]cm^{3} h = 15 cm\\r = ? d = ? At = ?\\V = pi.r^{2}.h r = \sqrt{V/(pi.h)}\\r = \sqrt{423cm^{3}/(3.1416)(15 cm) }\\r = \sqrt{(423,9 / 47,124) cm^{2} } = \sqrt{9 cm^{2} } \\r = 3 cm \\ d = 2r \\ d = 2.3 cm \\ d = 6 cm[/tex]
At = 2. pi. r . (h - r)
At = 2(3,1416)(3 cm)(15 cm - 3 cm)
At = (18,85 cm)(12 cm)
At = 226,2 [tex]cm^{2}[/tex]
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Respuesta:
d = 6 cm At = 226,2 [tex]cm^{2}[/tex]
Explicación paso a paso:
v = 423,9 [tex]cm^{3}[/tex]
[tex]cm^{3} h = 15 cm\\r = ? d = ? At = ?\\V = pi.r^{2}.h r = \sqrt{V/(pi.h)}\\r = \sqrt{423cm^{3}/(3.1416)(15 cm) }\\r = \sqrt{(423,9 / 47,124) cm^{2} } = \sqrt{9 cm^{2} } \\r = 3 cm \\ d = 2r \\ d = 2.3 cm \\ d = 6 cm[/tex]
At = 2. pi. r . (h - r)
At = 2(3,1416)(3 cm)(15 cm - 3 cm)
At = (18,85 cm)(12 cm)
At = 226,2 [tex]cm^{2}[/tex]