En general la distancia entre dos puntos es d = √[(x - x')² + (y - y')²]
a) El segmento horizontal mide 6 - 1 = 5 m
El segmento oblicuo mide √[(11 - 6)² + ( 7 - 2)² = 7,07 m
Total: 5 m + 7,07 m = 12,07 m
b) Δs = √[(11 - 1)² + (7 - 2)²] = 11,2 m
c) Rm = 12,07 m / 10 s = 1,207 m/s
d) Vm = 11,2 m / 10 s = 1,12 m/s
Saludos
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En general la distancia entre dos puntos es d = √[(x - x')² + (y - y')²]
a) El segmento horizontal mide 6 - 1 = 5 m
El segmento oblicuo mide √[(11 - 6)² + ( 7 - 2)² = 7,07 m
Total: 5 m + 7,07 m = 12,07 m
b) Δs = √[(11 - 1)² + (7 - 2)²] = 11,2 m
c) Rm = 12,07 m / 10 s = 1,207 m/s
d) Vm = 11,2 m / 10 s = 1,12 m/s
Saludos