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2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O
6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂
C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
2) Balancee e indique el coeficiente del agua = 2
3 I₂ + 10 HNO₃ → 6 HIO₃ + 10 NO + 2 H₂O
3) Balancea por redox
ₓ=₊₄ ₓ=₊₂
ₓ₋₄=₀ ₓ₋₂=₀
ₓ -₂=₀ ₊₁₋₁=₀ ₓ₋₁=₀ ₀
PbO₂ + HCl → PbCl₂ + Cl₂ + H₂O
semi reacciones
Pb⁺⁴ + 2 e →→ Pb⁺² ⇒⇒ se reduce- gana electrones
2 Cl⁻¹ →→ Cl⁰₂ + 2e ⇒⇒ se oxida - pierde electrones
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
Pb + 2 Cl → Pb + Cl₂
PbO₂ + 4 HCl → PbCl₂ + Cl₂ + 2 H₂O