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M = mol soluto / V (L)
mol = masa/Mm
Mm NaNO3 = 85 g/mol
mol = 25 g / 85 g/mol = 0.294 mol
v = 250 mL / 1000 = 0.250 L
M = 0.294 mol / 0.250 L
M= 1.176 mol/L
M SOLUCIÓN = MASA SOLUTO + MASA SOLVENTE
masa solución = 25 g + 250 g = 275 g
% m/m masa soluto / masa solucion x 100
% m/m = 25 g / 275 g x 100 = 9.09 %
molalidad = moles soluto / Kg solvente
m = 0.294 mol / 0.25 Kg = 1.18 mol/Kg
B.- 25g de cloruro sódico NaCL en 750g de disolucion. El volumen de disolucion es 750ml.
M = mol soluto / V (L)
mol = masa/Mm
Mm NaCl = 58,44 g/mol
mol = 25 g / 58.44 g/mol = 0.428 mol
v = 750 mL / 1000 = 0.750 L
M = 0.428 mol / 0.750 L
M= 0.57 mol/L
M SOLUCIÓN = MASA SOLUTO + MASA SOLVENTE
masa solución = 25 g + 750 g = 775 g
% m/m masa soluto / masa solucion x 100
% m/m = 25 g / 775 g x 100 = 3.23 %
molalidad = moles soluto / Kg solvente
m = 0.428 mol /( 0.750 - 0.025) Kg = 0.59 mol/Kg
C.- 50g de nitrato sódico NaNO3 en 1 litro de agua
M = mol soluto / V (L)
mol = masa/Mm
Mm NaNO3 = 85 g/mol
mol = 50 g / 85 g/mol = 0.588 mol
m = 1000 g
M = 0.588 mol / 1 L
M = 0.588 mol/L
M SOLUCIÓN = MASA SOLUTO + M SOLVENTE
M solución = 50 g + 1000 g = 1050 g
% m/v masa soluto / v solucion x 100
% m/m = 50 g / 1050 g x 100 = 4.762 %
molalidad = moles soluto / Kg solvente
m = 0.588 mol / 1 Kg = 0.588 mol/Kg