Explicación paso a paso:
Círculo:
P=2πr
P=2π(4)
P=25.132741228718cm
Rectangulo:
A=bh
A=
[tex]6 \times \frac{7}{9} = \frac{6}{1} \times \frac{7}{9} = \frac{42}{9} = \frac{14}{3} [/tex]
A=14/3cm²
[tex]9 \times \frac{2}{5} = \frac{9}{1} \times \frac{2}{5} = \frac{18}{5} = 3 \frac{3}{5} [/tex]
A=3 3/5cm²
Triángulo:
A=bh/2
[tex]( \frac{3}{4} \times \frac{3}{4} ) \div 2 = \frac{9}{16} \div 2 = \frac{9}{16} \div \frac{2}{1} = \frac{9}{32} [/tex]
A=9/32 cm²
1)
P=l+l+l+l
P=50+20+50+20
P=140cm
2)
b=15.2m
h=12.4m
A=(15.2m)(12.4m)
A=188.48m²
188.48m² × $32.00=
$6,031.36
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Explicación paso a paso:
Círculo:
P=2πr
P=2π(4)
P=25.132741228718cm
Rectangulo:
A=bh
A=
[tex]6 \times \frac{7}{9} = \frac{6}{1} \times \frac{7}{9} = \frac{42}{9} = \frac{14}{3} [/tex]
A=14/3cm²
A=
[tex]9 \times \frac{2}{5} = \frac{9}{1} \times \frac{2}{5} = \frac{18}{5} = 3 \frac{3}{5} [/tex]
A=3 3/5cm²
Triángulo:
A=bh/2
A=
[tex]( \frac{3}{4} \times \frac{3}{4} ) \div 2 = \frac{9}{16} \div 2 = \frac{9}{16} \div \frac{2}{1} = \frac{9}{32} [/tex]
A=9/32 cm²
1)
P=l+l+l+l
P=50+20+50+20
P=140cm
2)
A=bh
b=15.2m
h=12.4m
A=(15.2m)(12.4m)
A=188.48m²
188.48m² × $32.00=
$6,031.36