Respuesta:
sen 180°=0
sen 90°=1
cos 180°= – 1
cos 90°= 0
H=(2 * 0 – 1)²+ (3 *(–1) – 0)²
H= (–1)²+(–3)²
H= 1+3
H= 4
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Respuesta:
sen 180°=0
sen 90°=1
cos 180°= – 1
cos 90°= 0
H=(2 * 0 – 1)²+ (3 *(–1) – 0)²
H= (–1)²+(–3)²
H= 1+3
H= 4