Respuesta:
es la b) x2 - 1 si tienes mas avisame
Explicación paso a paso:
[tex]( \frac{1}{1 - x} - \frac{1}{1 + x} )( \frac{1 - {x}^{2} }{2x} )[/tex]
[tex]( \frac{1 + x - (1 - x)}{(1 - x)(1 + x)} )( \frac{(1 + x)(1 - x)}{2x} )[/tex]
[tex]( \frac{1 + x - 1 + x}{(1 - x)(1 +x)} )( \frac{(1 + x)(1 - x)}{2x} )[/tex]
[tex] \frac{x + x}{2x} = \frac{2x}{2x} = 1[/tex]
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Respuesta:
es la b) x2 - 1 si tienes mas avisame
Verified answer
Explicación paso a paso:
[tex]( \frac{1}{1 - x} - \frac{1}{1 + x} )( \frac{1 - {x}^{2} }{2x} )[/tex]
[tex]( \frac{1 + x - (1 - x)}{(1 - x)(1 + x)} )( \frac{(1 + x)(1 - x)}{2x} )[/tex]
[tex]( \frac{1 + x - 1 + x}{(1 - x)(1 +x)} )( \frac{(1 + x)(1 - x)}{2x} )[/tex]
[tex] \frac{x + x}{2x} = \frac{2x}{2x} = 1[/tex]