Respuesta:
[tex]x = 1[/tex]
Explicación paso a paso:
Dado la expresión:
[tex] log(6x - 1) - log(x + 4) = log(x) \\ [/tex]
Por propiedad:
[tex] log(a) - log(b) = log( \frac{a}{b} ) [/tex]
Entonces:
[tex] log( \frac{6x - 1}{x + 4} ) = log( x ) [/tex]
[tex] \frac{6x - 1}{x + 4} = x \\ 6x - 1 = {x}^{2} + 4x \\ 0 = {x}^{2} - 2x + 1 \\ 0 = {(x - 1)}^{2} \\ 0 = x - 1 \\ 1 = x[/tex]
Escorpio.. ;D
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
[tex]x = 1[/tex]
Explicación paso a paso:
Dado la expresión:
[tex] log(6x - 1) - log(x + 4) = log(x) \\ [/tex]
Por propiedad:
[tex] log(a) - log(b) = log( \frac{a}{b} ) [/tex]
Entonces:
[tex] log( \frac{6x - 1}{x + 4} ) = log( x ) [/tex]
[tex] \frac{6x - 1}{x + 4} = x \\ 6x - 1 = {x}^{2} + 4x \\ 0 = {x}^{2} - 2x + 1 \\ 0 = {(x - 1)}^{2} \\ 0 = x - 1 \\ 1 = x[/tex]
Escorpio.. ;D