Explicación paso a paso:
[tex] \frac{6}{9x + 1} = \frac{9}{5x - 2} [/tex]
Los denominadores pasan a multiplicar al numenador opuesto.
(5x-2)6=9(9x+1)
30x-12=81x+9
-51x=21
[tex]x = - \frac{21}{51} [/tex]
Sacamos 7ma
[tex]x = - \frac{7}{17} [/tex]
Despeja para x
Multiplicas en cruz
[tex]6(5x - 2) = 9(9x + 1)[/tex]
[tex]30x - 12 = 81x + 9[/tex]
[tex] - 12 = 81x + 9 - 30x[/tex]
[tex] - 12 = 51x + 9[/tex]
[tex] - 12 - 9 = 51x[/tex]
[tex] - 21 = 51x[/tex]
[tex] - \frac{21}{51} = x[/tex]
[tex] - \frac{7}{17} = x[/tex]
[tex] \red{x = }- \frac{7}{17} [/tex] ← Respuesta
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Verified answer
Explicación paso a paso:
Hola , bueno te explicaré:
[tex] \frac{6}{9x + 1} = \frac{9}{5x - 2} [/tex]
Los denominadores pasan a multiplicar al numenador opuesto.
(5x-2)6=9(9x+1)
30x-12=81x+9
-51x=21
[tex]x = - \frac{21}{51} [/tex]
Sacamos 7ma
[tex]x = - \frac{7}{17} [/tex]
Despeja para x
[tex] \frac{6}{9x + 1} = \frac{9}{5x - 2} [/tex]
Multiplicas en cruz
[tex]6(5x - 2) = 9(9x + 1)[/tex]
[tex]30x - 12 = 81x + 9[/tex]
[tex] - 12 = 81x + 9 - 30x[/tex]
[tex] - 12 = 51x + 9[/tex]
[tex] - 12 - 9 = 51x[/tex]
[tex] - 21 = 51x[/tex]
[tex] - \frac{21}{51} = x[/tex]
[tex] - \frac{7}{17} = x[/tex]
[tex] \red{x = }- \frac{7}{17} [/tex] ← Respuesta