Respuesta:
[tex]2) 2x + 4y = 0 \\ 2x = - 4y \\ x = \frac{ - 4y}{2} \\ 1) 3x - 4y = - 6 \\ 3 \times \frac{ - 4y}{2} - 4y = - 6 \\ \frac{ - 12y}{2} - \frac{ - 8y}{2} = - 6 \\ \frac{ - 20y}{2} = - 6 \\ - 20y = - 12 \\ 20y = 12 \\ y = \frac{12}{20} = \frac{3}{5 } \\ y = \frac{3}{5} [/tex]
[tex]x = \frac{ - 4y}{2} = \frac{ - 4 \times \frac{ - 3}{5} }{2} = \frac{ \frac{ - 12}{5} }{2} \\ = \frac{ - 12}{5} \times \frac{1}{2} = \frac{ - 12}{10} = \frac{ - 6}{5} [/tex]
[tex]3 \times \frac{ - 6}{5} - 4 \times \frac{3}{5} = \frac{ - 18}{5} - \frac{12}{5} = \frac{ - 30}{5} = - 6[/tex]
[tex]2 \times \frac{ - 6}{5} + 4 \times \frac{3}{5} = \frac{ - 12}{5} + \frac{12}{5} = 0[/tex]
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Respuesta:
[tex]2) 2x + 4y = 0 \\ 2x = - 4y \\ x = \frac{ - 4y}{2} \\ 1) 3x - 4y = - 6 \\ 3 \times \frac{ - 4y}{2} - 4y = - 6 \\ \frac{ - 12y}{2} - \frac{ - 8y}{2} = - 6 \\ \frac{ - 20y}{2} = - 6 \\ - 20y = - 12 \\ 20y = 12 \\ y = \frac{12}{20} = \frac{3}{5 } \\ y = \frac{3}{5} [/tex]
[tex]x = \frac{ - 4y}{2} = \frac{ - 4 \times \frac{ - 3}{5} }{2} = \frac{ \frac{ - 12}{5} }{2} \\ = \frac{ - 12}{5} \times \frac{1}{2} = \frac{ - 12}{10} = \frac{ - 6}{5} [/tex]
[tex]3 \times \frac{ - 6}{5} - 4 \times \frac{3}{5} = \frac{ - 18}{5} - \frac{12}{5} = \frac{ - 30}{5} = - 6[/tex]
[tex]2 \times \frac{ - 6}{5} + 4 \times \frac{3}{5} = \frac{ - 12}{5} + \frac{12}{5} = 0[/tex]
espero te sirva