Respuesta:
#1
[tex] \frac{2 {x}^{6} - 4 {x}^{4} + {x}^{2} }{2 {x}^{2} } = \frac{ {x}^{2}(2 {x}^{4} - 4 {x}^{2} + 1) }{2 {x}^{2} } = \frac{2 {x}^{4} - 4 {x}^{2} + 1}{2} [/tex]
#2
[tex] \frac{3 {x}^{2} + 11x + 6 }{x + 3} = \frac{(x+3)(3x+2)}{x + 3} = \frac{3x + 2}{1} = 3x + 2[/tex]
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Verified answer
Respuesta:
#1
[tex] \frac{2 {x}^{6} - 4 {x}^{4} + {x}^{2} }{2 {x}^{2} } = \frac{ {x}^{2}(2 {x}^{4} - 4 {x}^{2} + 1) }{2 {x}^{2} } = \frac{2 {x}^{4} - 4 {x}^{2} + 1}{2} [/tex]
#2
[tex] \frac{3 {x}^{2} + 11x + 6 }{x + 3} = \frac{(x+3)(3x+2)}{x + 3} = \frac{3x + 2}{1} = 3x + 2[/tex]