Explicación paso a paso:
10)
[tex] \sqrt{6} ^{2} + { \sqrt{10} }^{2} = {x}^{2} \\ x = \sqrt{6 + 10} \\ x = 4[/tex]
12)
[tex] {x}^{2} = \sqrt{5} ^{2} + \sqrt{11} ^{2} \\ {x}^{2} = 16 \\ x = 4 [/tex]
14)
x=3
y=17
x=6
Suma=26
16)
[tex] {5}^{2} + \sqrt{24} ^{2} = {x}^{2} \\ 25 + 24 = {x}^{2} \\ 49 = {x}^{2} \\ x = 7[/tex]
Respuesta:
la pura mafrderfrdutt8
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Verified answer
Explicación paso a paso:
10)
[tex] \sqrt{6} ^{2} + { \sqrt{10} }^{2} = {x}^{2} \\ x = \sqrt{6 + 10} \\ x = 4[/tex]
12)
[tex] {x}^{2} = \sqrt{5} ^{2} + \sqrt{11} ^{2} \\ {x}^{2} = 16 \\ x = 4 [/tex]
14)
x=3
y=17
x=6
Suma=26
16)
[tex] {5}^{2} + \sqrt{24} ^{2} = {x}^{2} \\ 25 + 24 = {x}^{2} \\ 49 = {x}^{2} \\ x = 7[/tex]
Respuesta:
la pura mafrderfrdutt8