Explicación paso a paso:
a)
[tex]3x + 1 = x - 1 \\ 3x - x + 1 = - 1 \\ 2x + 1 = - 1 \\ 2x = - 1 - 1 \\ 2x = - 2 \\ x = \frac{ - 2}{2} \\ x = - 1[/tex]
verificar:
[tex]3( - 1) + 1 = ( - 1) - 1 \\ - 3 + 1 = - 2 \\ - 2 = - 2[/tex]
b)
[tex]10x + 15 = 5x + 8 \\ 10x - 5x + 15 = 8 \\ 5x + 15 = 8 \\ 5x = 8 - 15 \\ 5x = - 7 \\ x = \frac { - 7}{5} [/tex]
verificar
[tex]5(2( \frac{ - 7}{5}) + 3) =5 ( \frac{ - 7}{5} ) + 8 \\ 5( \frac{ - 14}{5} + 3) = - 7 + 8\\ 5( \frac{ - 14}{5} + \frac{15}{5}) = 1 \\ 5( \frac{1}{5}) = 1 \\ 1 = 1[/tex]
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Explicación paso a paso:
a)
[tex]3x + 1 = x - 1 \\ 3x - x + 1 = - 1 \\ 2x + 1 = - 1 \\ 2x = - 1 - 1 \\ 2x = - 2 \\ x = \frac{ - 2}{2} \\ x = - 1[/tex]
verificar:
[tex]3( - 1) + 1 = ( - 1) - 1 \\ - 3 + 1 = - 2 \\ - 2 = - 2[/tex]
b)
[tex]10x + 15 = 5x + 8 \\ 10x - 5x + 15 = 8 \\ 5x + 15 = 8 \\ 5x = 8 - 15 \\ 5x = - 7 \\ x = \frac { - 7}{5} [/tex]
verificar
[tex]5(2( \frac{ - 7}{5}) + 3) =5 ( \frac{ - 7}{5} ) + 8 \\ 5( \frac{ - 14}{5} + 3) = - 7 + 8\\ 5( \frac{ - 14}{5} + \frac{15}{5}) = 1 \\ 5( \frac{1}{5}) = 1 \\ 1 = 1[/tex]