Respuesta:
6
Explicación paso a paso:
Aplicando Teorema de Pitágoras
h² = 1² + √5²
h² = 1 + √25
h² = 1 + 5
h = √6
[tex]sec \beta = \frac{ \sqrt{6} }{1} \\ \cos( \beta ) \frac{1}{ \sqrt{6} } \\ \frac{sec \beta }{ \cos( \beta ) } = \frac{ \frac{ \sqrt{6} }{1} }{ \frac{1}{ \sqrt{6} } } = ( \sqrt{6} {)}^{2} = 6[/tex]
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Respuesta:
6
Explicación paso a paso:
Aplicando Teorema de Pitágoras
h² = 1² + √5²
h² = 1 + √25
h² = 1 + 5
h = √6
[tex]sec \beta = \frac{ \sqrt{6} }{1} \\ \cos( \beta ) \frac{1}{ \sqrt{6} } \\ \frac{sec \beta }{ \cos( \beta ) } = \frac{ \frac{ \sqrt{6} }{1} }{ \frac{1}{ \sqrt{6} } } = ( \sqrt{6} {)}^{2} = 6[/tex]