Respuesta:
Usando:
[tex]\frac{a}{b} \pm \frac{c}{d} = \frac{ad\pm bc}{bd}[/tex]
a)
[tex]\frac{3}{4}+\frac{8}{3} = \frac{3(3)+4(8)}{4(3)} = \frac{9+32}{12} = \bold{\frac{41}{12}}[/tex](no se puede simplificar)
b)
[tex]\frac{3}{5}-\frac{2}{5} = \frac{3(5)-2(5)}{5(5)} = \frac{15-10}{25} = \frac{5}{25} = \frac{5\div5}{25\div5}= \bold{\frac{1}{5}}[/tex](simplificación máxima)
c)
[tex]\frac{2}{5}.\frac{8}{20} = \frac{2(8)}{5(20)} = \frac{16}{100} = \frac{16\div2}{100\div2} = \frac{8}{50} = \frac{8\div2}{50\div2} = \bold{\frac{4}{25}}[/tex](simplificación máxima)
d)
[tex]\frac{9}{10}:\frac{3}{14} = \frac{9}{10}.\frac{14}{3} = \frac{9(14)}{10(3)}=\frac{126}{30} = \frac{126}{30} = \frac{126\div6}{30\div6} = \bold{\frac{21}{5}}[/tex](simplificación máxima)
Explicación paso a paso:
Espero te sirva
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Verified answer
Respuesta:
Usando:
[tex]\frac{a}{b} \pm \frac{c}{d} = \frac{ad\pm bc}{bd}[/tex]
a)
[tex]\frac{3}{4}+\frac{8}{3} = \frac{3(3)+4(8)}{4(3)} = \frac{9+32}{12} = \bold{\frac{41}{12}}[/tex](no se puede simplificar)
b)
[tex]\frac{3}{5}-\frac{2}{5} = \frac{3(5)-2(5)}{5(5)} = \frac{15-10}{25} = \frac{5}{25} = \frac{5\div5}{25\div5}= \bold{\frac{1}{5}}[/tex](simplificación máxima)
c)
[tex]\frac{2}{5}.\frac{8}{20} = \frac{2(8)}{5(20)} = \frac{16}{100} = \frac{16\div2}{100\div2} = \frac{8}{50} = \frac{8\div2}{50\div2} = \bold{\frac{4}{25}}[/tex](simplificación máxima)
d)
[tex]\frac{9}{10}:\frac{3}{14} = \frac{9}{10}.\frac{14}{3} = \frac{9(14)}{10(3)}=\frac{126}{30} = \frac{126}{30} = \frac{126\div6}{30\div6} = \bold{\frac{21}{5}}[/tex](simplificación máxima)
Explicación paso a paso:
Espero te sirva