Respuesta:
4x+3y=2
-3x-2y=-1
usando el metodo de sustitucion
x=[tex]\frac{2-3y}{4}[/tex]
-3((2-3y)/4)-2y=-1
[tex]\frac{-6+9y-8y}{4} =-1[/tex]
Y=-4+6
Y=2
[tex]x=\frac{2-3(2)}{4}[/tex]
X=-1
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Respuesta:
4x+3y=2
-3x-2y=-1
usando el metodo de sustitucion
4x+3y=2
x=[tex]\frac{2-3y}{4}[/tex]
-3x-2y=-1
-3((2-3y)/4)-2y=-1
[tex]\frac{-6+9y-8y}{4} =-1[/tex]
Y=-4+6
Y=2
x=[tex]\frac{2-3y}{4}[/tex]
[tex]x=\frac{2-3(2)}{4}[/tex]
X=-1