{2x + y = 9
{3x - y = 1
{y = 9 - 2x
3x - (9 - 2x) = 1
3x - 9 + 2x = 1
5x - 9 = 1
5x = 9 + 1
5x = 10
x = 2
y = 9 - 2 × 2
y = 9 - 4
y = 5
__________________________
[tex] - 4 \: < \: x \: \leqslant \: 5[/tex]
▪Escribimos en intervalo:
[tex] \boxed{ \bold{x \: ∈ \: (-4, 5]}}[/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Primer problema:
{2x + y = 9
{3x - y = 1
{y = 9 - 2x
{3x - y = 1
Para x...
3x - (9 - 2x) = 1
3x - 9 + 2x = 1
5x - 9 = 1
5x = 9 + 1
5x = 10
x = 2
Para y...
y = 9 - 2 × 2
y = 9 - 4
y = 5
R// (x, y) = (2, 5)
__________________________
Segundo problema:
[tex] - 4 \: < \: x \: \leqslant \: 5[/tex]
▪Escribimos en intervalo:
[tex] \boxed{ \bold{x \: ∈ \: (-4, 5]}}[/tex]