Propiedad:
A[tex]_{circulo\\[/tex] = πr²
Solucion:
A₁ = π . 9²
= π . 81
= 81π cm²
A₂ = π . 7²
= π . 49
= 49π cm²
Se resta:
= 81π - 49π
= 32π
π = 3.14
= 32 . π
= 32 . 3.14
= 100.48
Espero te haya ayudado:)
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Propiedad:
A[tex]_{circulo\\[/tex] = πr²
Solucion:
A₁ = π . 9²
= π . 81
= 81π cm²
A₂ = π . 7²
= π . 49
= 49π cm²
Se resta:
= 81π - 49π
= 32π
π = 3.14
= 32 . π
= 32 . 3.14
= 100.48
Espero te haya ayudado:)