Explicación paso a paso:
25. (-13a⁵b² + 16a³b³ - 14) - (-3a³b³ + 17 - 19a⁵b²)=
-13a⁵b² + 16a³b³ - 14 + 3a³b³ - 17 + 19a⁵b²=
-13a⁵b²+ 19a⁵b² + 16a³b³ + 3a³b³ -14 - 17=
6a⁵b² + 19a³b³ - 31
26. (27bx + 3b - 8x - 6) - (12bx + 3b + 5x - 13)=
27bx + 3b - 8x - 6 - 12bx - 3b - 5x + 13=
27bx - 12bx + 3b - 3b -8x - 5x - 6 + 13=
15bx -13x + 7
27. (5,3m⁴n³ - 2,5m³n⁴ + 2,8m²n⁵) - (-3,1m³n⁴ + 1,3m⁴n³ - 0,8m⁸n⁵)=
5,3m⁴n³ - 2,5m³n⁴ + 2,8m²n⁵ + 3,1m³n⁴ - 1,3m⁴n³ + 0,8m⁸n⁵=
5,3m⁴n³ - 1,3m⁴n³ - 2,5m³n⁴ + 3,1m³n⁴ + 2,8m²n⁵ + 0,8m⁸n⁵=
4m⁴n³ + 0,6m³n⁴ + 2,8m²n⁵ + 0,8m⁸n⁵
28.
[tex]( \frac{5}{8} {h}^{2} - \frac{2}{3}h - \frac{1}{2} k + 34) - ( - \frac{3}{2} h - \frac{5}{8} k + \frac{5}{16} {h}^{2} - 67) = \\ \frac{5}{8} {h}^{2} - \frac{2}{3}h - \frac{1}{2} k + 34 + \frac{3}{2} h + \frac{5}{8} k - \frac{5}{16} {h}^{2} + 67 = \\ \frac{5}{8} {h}^{2} - \frac{5}{16} {h}^{2} - \frac{2}{3} h + \frac{3}{2} h - \frac{1}{2} k + \frac{5}{8} k + 34 + 67 = \\ \frac{10}{16} {h}^{2} - \frac{5}{16} {h}^{2} - \frac{4}{6} h + \frac{9}{6} h - \frac{4}{8} k + \frac{5}{8} k + 34 + 67 = \\ \frac{5}{16} {h}^{2} + \frac{5}{6} h + \frac{1}{8} k + 101[/tex]
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Verified answer
Explicación paso a paso:
25. (-13a⁵b² + 16a³b³ - 14) - (-3a³b³ + 17 - 19a⁵b²)=
-13a⁵b² + 16a³b³ - 14 + 3a³b³ - 17 + 19a⁵b²=
-13a⁵b²+ 19a⁵b² + 16a³b³ + 3a³b³ -14 - 17=
6a⁵b² + 19a³b³ - 31
26. (27bx + 3b - 8x - 6) - (12bx + 3b + 5x - 13)=
27bx + 3b - 8x - 6 - 12bx - 3b - 5x + 13=
27bx - 12bx + 3b - 3b -8x - 5x - 6 + 13=
15bx -13x + 7
27. (5,3m⁴n³ - 2,5m³n⁴ + 2,8m²n⁵) - (-3,1m³n⁴ + 1,3m⁴n³ - 0,8m⁸n⁵)=
5,3m⁴n³ - 2,5m³n⁴ + 2,8m²n⁵ + 3,1m³n⁴ - 1,3m⁴n³ + 0,8m⁸n⁵=
5,3m⁴n³ - 1,3m⁴n³ - 2,5m³n⁴ + 3,1m³n⁴ + 2,8m²n⁵ + 0,8m⁸n⁵=
4m⁴n³ + 0,6m³n⁴ + 2,8m²n⁵ + 0,8m⁸n⁵
28.
[tex]( \frac{5}{8} {h}^{2} - \frac{2}{3}h - \frac{1}{2} k + 34) - ( - \frac{3}{2} h - \frac{5}{8} k + \frac{5}{16} {h}^{2} - 67) = \\ \frac{5}{8} {h}^{2} - \frac{2}{3}h - \frac{1}{2} k + 34 + \frac{3}{2} h + \frac{5}{8} k - \frac{5}{16} {h}^{2} + 67 = \\ \frac{5}{8} {h}^{2} - \frac{5}{16} {h}^{2} - \frac{2}{3} h + \frac{3}{2} h - \frac{1}{2} k + \frac{5}{8} k + 34 + 67 = \\ \frac{10}{16} {h}^{2} - \frac{5}{16} {h}^{2} - \frac{4}{6} h + \frac{9}{6} h - \frac{4}{8} k + \frac{5}{8} k + 34 + 67 = \\ \frac{5}{16} {h}^{2} + \frac{5}{6} h + \frac{1}{8} k + 101[/tex]