Respuesta:
4) [tex]\frac{17}{4}-1\frac{2}{4}=\frac{17}{4}-\frac{6}{4}=\frac{17-6}{4}=\frac{11}{4}=2\frac{3}{4},,[/tex]
6) [tex]2\frac{1}{3}-\frac{4}{3}=\frac{7}{3}-\frac{4}{3}=\frac{7-4}{3}=\frac{3}{3}=1,,[/tex]
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Verified answer
Respuesta:
4) [tex]\frac{17}{4}-1\frac{2}{4}=\frac{17}{4}-\frac{6}{4}=\frac{17-6}{4}=\frac{11}{4}=2\frac{3}{4},,[/tex]
6) [tex]2\frac{1}{3}-\frac{4}{3}=\frac{7}{3}-\frac{4}{3}=\frac{7-4}{3}=\frac{3}{3}=1,,[/tex]