Respuesta:
[tex]\frac{14}{15}[/tex]
Explicación paso a paso:
[tex]\frac{(\frac{2}{3}+1-\frac{1}{2})\frac{6}{5} }{\frac{1}{3}( 4+\frac{1}{2} )}[/tex]
yo usare el metodo de convertir todo [tex]\frac{x}{6}[/tex] porque 2 x 2=4 y no 3.
y el de abajo a [tex]\frac{x}{2}[/tex]
[tex]\frac{(\frac{4}{6}+\frac{6}{6} -\frac{3}{6})\frac{6}{5} }{\frac{1}{3}( \frac{8}{2} +\frac{1}{2} )}[/tex]
[tex]\frac{(\frac{7}{6} )\frac{6}{5} }{\frac{1}{3}( \frac{9}{2} )}[/tex]
[tex]\frac{\frac{7}{5} }{ \frac{3}{2} }[/tex]
[tex]\frac{7.2}{5.3}[/tex]
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Respuesta:
[tex]\frac{14}{15}[/tex]
Explicación paso a paso:
[tex]\frac{(\frac{2}{3}+1-\frac{1}{2})\frac{6}{5} }{\frac{1}{3}( 4+\frac{1}{2} )}[/tex]
yo usare el metodo de convertir todo [tex]\frac{x}{6}[/tex] porque 2 x 2=4 y no 3.
y el de abajo a [tex]\frac{x}{2}[/tex]
[tex]\frac{(\frac{4}{6}+\frac{6}{6} -\frac{3}{6})\frac{6}{5} }{\frac{1}{3}( \frac{8}{2} +\frac{1}{2} )}[/tex]
[tex]\frac{(\frac{7}{6} )\frac{6}{5} }{\frac{1}{3}( \frac{9}{2} )}[/tex]
[tex]\frac{\frac{7}{5} }{ \frac{3}{2} }[/tex]
[tex]\frac{7.2}{5.3}[/tex]