Respuesta:
masa molar del CaCO3=100g/mol
[tex]145g \: caco3. \frac{6.022. {10}^{23} molec \: }{100g \: caco3}. \frac{3atomos \: o}{1 \: molec} = 2.62. {10}^{24} atomos \: de \: o[/tex]
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Respuesta:
masa molar del CaCO3=100g/mol
[tex]145g \: caco3. \frac{6.022. {10}^{23} molec \: }{100g \: caco3}. \frac{3atomos \: o}{1 \: molec} = 2.62. {10}^{24} atomos \: de \: o[/tex]