Respuesta:
[tex](x + 2) {}^{2} + (3x - 2) \times (x + 1) = \\ (3x - 2) \times (x + 1) = + 1x + 1x = + 2x \\ (x + 2) {}^{2} = + 4x {}^{2} \\ + 2x + 4x {}^{2} = + 6x {}^{3} [/tex]
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Respuesta:
[tex](x + 2) {}^{2} + (3x - 2) \times (x + 1) = \\ (3x - 2) \times (x + 1) = + 1x + 1x = + 2x \\ (x + 2) {}^{2} = + 4x {}^{2} \\ + 2x + 4x {}^{2} = + 6x {}^{3} [/tex]