Hola! :3
Aplicamos la siguiente fórmula:
(x + a)(x + b) = x² + (a + b)x + ab
Reemplazamos:
(x + 7)(x + 1) = (x + 2)(x + 5)
x² + (7 + 1)x + 7(1) = x² + (2 + 5)x + 2(5)
x² + 8x + 7 = x² + 7x + 10
x² - x² + 8x - 7x = 10 - 7
0x² + (8 - 7)x = 3
1x = 3
x = 3
Espero haberte ayudado :D
Atte: Jean07122006
" Life is not a problem to be solved but a reality to be experienced! "
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Hola! :3
Aplicamos la siguiente fórmula:
(x + a)(x + b) = x² + (a + b)x + ab
Reemplazamos:
(x + 7)(x + 1) = (x + 2)(x + 5)
x² + (7 + 1)x + 7(1) = x² + (2 + 5)x + 2(5)
x² + 8x + 7 = x² + 7x + 10
x² - x² + 8x - 7x = 10 - 7
0x² + (8 - 7)x = 3
1x = 3
x = 3
Espero haberte ayudado :D
Atte: Jean07122006