[tex] \frac{ {a}^{ {2}^{3} }. {a}^{ {2}^{2} } }{ {a}^{ {3}^{2} } } = \frac{ {a}^{8} . {a}^{4} }{ {a}^{9} } = \frac{ {a}^{8 + 4} }{ {a}^{9} } = \frac{ {a}^{12} }{ {a}^{9} } = {a}^{12 - 9} = {a}^{3} [/tex]
De modo que: A = a³
Si A = 8, entonces:
[tex]8 = {a}^{3} \\ \sqrt[3]{8} = a \\ 2 = a[/tex]
Respuesta: A) 2
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[tex] \frac{ {a}^{ {2}^{3} }. {a}^{ {2}^{2} } }{ {a}^{ {3}^{2} } } = \frac{ {a}^{8} . {a}^{4} }{ {a}^{9} } = \frac{ {a}^{8 + 4} }{ {a}^{9} } = \frac{ {a}^{12} }{ {a}^{9} } = {a}^{12 - 9} = {a}^{3} [/tex]
De modo que: A = a³
Si A = 8, entonces:
[tex]8 = {a}^{3} \\ \sqrt[3]{8} = a \\ 2 = a[/tex]
Respuesta: A) 2