AYUDAA con procedimiento
1) 15t - 20 = 6t - (2t+ 2) + (- 5t + 3)
2) 4(r + 5) - 5(- 2r - 6) = 8(2r + 1) - 3(2r + 3)
1) 15t - 20 = 6t - (2t+ 2) + (- 5t + 3)
2) 4(r + 5) - 5(- 2r - 6) = 8(2r + 1) - 3(2r + 3)
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Hola!
Explicación paso a paso:
1) 15t - 20 = 6t - (2t+ 2) + (- 5t + 3)
15t - 20 = 6t - 2t - 2 - 5t + 3
15t - 20 = - 1t + 1
15t + 1t = 1 + 20
16t = 21
t = [tex]\frac{21}{16}[/tex]
2) 4(r + 5) - 5(- 2r - 6) = 8(2r + 1) - 3(2r + 3)
4r + 20 + 10r + 30 = 16r + 8 - 6r - 9
14r + 50 = 10r - 1
14r - 10r = - 1 - 50
4r = -51
r = [tex]\frac{-51}{4}[/tex]
Espero te sirva :)✨