Para hallar las dimensiones :
x²+4² = (x+2)²
x²+16 = x²+4x+4
12 = 4x
x = 3
_____
Hipotenusa : 5u
Piden hallar E = 5(sen.a-cos.a )
E = 5(4/5 -3/5)
E = 5(1/5)
E = 1
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Para hallar las dimensiones :
x²+4² = (x+2)²
x²+16 = x²+4x+4
12 = 4x
x = 3
_____
Hipotenusa : 5u
_____
Piden hallar E = 5(sen.a-cos.a )
E = 5(4/5 -3/5)
E = 5(1/5)
E = 1
Respuesta = E = 1