Respuesta:
Hola es a
Explicación paso a paso:
x2−2x−6=0
(1)⋅x2+(−2)⋅x+(−6)=0
x=−(−2)±(−2)2−4⋅(−6)−−−−−−−−−−−−−−−√2
x=2±4−(−24)−−−−−−−−−√2
x=2±28−−√2
x=2±(2)⋅7–√2
x=(2)⋅[(1)±7–√](2)
x1=1+7–√
x2=1−7–√
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Respuesta:
Hola es a
Explicación paso a paso:
x2−2x−6=0
(1)⋅x2+(−2)⋅x+(−6)=0
x=−(−2)±(−2)2−4⋅(−6)−−−−−−−−−−−−−−−√2
x=2±4−(−24)−−−−−−−−−√2
x=2±28−−√2
x=2±(2)⋅7–√2
x=(2)⋅[(1)±7–√](2)
x1=1+7–√
x2=1−7–√