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x² + x = 12
x² + x - 12 = 0 Factorizas trinomio de la forma x² + bx + c
(x + 4)(x - 3) = 0 Tiene dos soluciones reales
x + 4 = 0
x = - 4
o
x - 3 = 0
x = 3
Solución.
(- 4 , 3)
x² + x - 12 = 0
x +4
x -3
4x-3x = x
(x + 4)(x - 3) = 0
x+4 = 0 x-3 = 0
x = -4 x = 3
CS = (-4;3)