Respuesta:
D) 4
Explicación paso a paso:
[tex]E= \sqrt{3} \ ctg210 + 2 cos 300\\\\* ctg 210: \ + ctg (210-180)= + ctg30 = \sqrt{3} \\\\*cos 300: \ +cos(360-300)= +cos60= \frac{1}{2}[/tex]
Reemplazamos:
[tex]E = \sqrt{3} . \sqrt{3} + 2.\frac{1}{2} \\\\E= \sqrt{3} ^{2} + 1\\\\E = 3 + 1\\\\E= 4[/tex]
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Verified answer
Respuesta:
D) 4
Explicación paso a paso:
[tex]E= \sqrt{3} \ ctg210 + 2 cos 300\\\\* ctg 210: \ + ctg (210-180)= + ctg30 = \sqrt{3} \\\\*cos 300: \ +cos(360-300)= +cos60= \frac{1}{2}[/tex]
Reemplazamos:
[tex]E = \sqrt{3} . \sqrt{3} + 2.\frac{1}{2} \\\\E= \sqrt{3} ^{2} + 1\\\\E = 3 + 1\\\\E= 4[/tex]