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Lo haré por suma y resta:
4(5x + 3y) = 4(5)
-5(4x +7y) = -5(27)
20x + 12y = 20
-20x - 35y = -135
20x + 12y - 20x - 35y = 20 - 135
-23y = -115
y = -115/(-23) = 5
Opción D
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