Question

ayuda porfiiii :((
no

Answer 1

Respuesta:

[tex] \sqrt{ \frac{3}{28} } [/tex]

Explicación paso a paso:

[tex] \tan( \alpha ) = \frac{co}{ca} [/tex]

[tex]co = \sqrt{3} [/tex]

[tex]ca = 5[/tex]

Solo falta hallar la Hipotenusa.

Para hallar la Hipotenusa se usa el Teorema de Pitágoras

[tex] {h}^{2} = {co}^{2} + {ca}^{2} \\ {h}^{2} = {( \sqrt{3}) }^{2} + {5}^{2} \\ {h}^{2} = 3 + 25 \\ h = \sqrt{28} \\ h = \sqrt{7 \times 2 \times 2} \\ h = \sqrt{7 \times {2}^{2} } \\ h = 2 \sqrt{7} [/tex]

[tex] \sin( \alpha ) = \frac{co}{h} [/tex]

[tex] \sin( \alpha ) = \frac{ \sqrt{3} }{2 \sqrt{7} } \\ \sin( \alpha ) = \frac{ \sqrt{3} }{2 \sqrt{7} } ( \frac{2 \sqrt{7} }{2 \sqrt{7} } ) \\ \sin( \alpha ) = \frac{2 \sqrt{21} }{4(7)} \\ \sin( \alpha ) = \frac{ \sqrt{21} }{14} = \sqrt{ \frac{3}{28} } [/tex]