Respuesta:
[tex]x+20=25\\\\x=25-20\\\\x=5[/tex] ✓ correcto
[tex]\frac{1}{3} y=64\\\\y=\frac{64.3}{1} \\\\y=192[/tex] ✓ correcto
[tex]6a-\frac{10}{3} =120\\\\6a=120-\frac{10}{3} \\\\a=\frac{370}{3} :6\\\\a=\frac{185}{9}[/tex] x incorrecto
[tex]9b+\frac{20}{6} =\frac{46}{3} \\\\9b=\frac{46}{3} -\frac{20}{6} \\\\9b=\frac{276-60}{18} \\\\9b=12\\\\b=\frac{12}{9} \\\\b= \frac{4}{3}[/tex] ✓ correcto
[tex]\sqrt{3} m-3=\sqrt{12} \\\\\sqrt{3} m=\sqrt{12} +3\\\\\sqrt{3}m=\sqrt{4.3} +3\\\\\sqrt{3}m=2\sqrt{3} +3\\\\m=\frac{2\sqrt{3}+3}{\sqrt{3} } \\\\m=2+\sqrt{3}[/tex] ✓correcto
Explicación paso a paso:
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Respuesta:
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Solución:
[tex]x+20=25\\\\x=25-20\\\\x=5[/tex] ✓ correcto
[tex]\frac{1}{3} y=64\\\\y=\frac{64.3}{1} \\\\y=192[/tex] ✓ correcto
[tex]6a-\frac{10}{3} =120\\\\6a=120-\frac{10}{3} \\\\a=\frac{370}{3} :6\\\\a=\frac{185}{9}[/tex] x incorrecto
[tex]9b+\frac{20}{6} =\frac{46}{3} \\\\9b=\frac{46}{3} -\frac{20}{6} \\\\9b=\frac{276-60}{18} \\\\9b=12\\\\b=\frac{12}{9} \\\\b= \frac{4}{3}[/tex] ✓ correcto
[tex]\sqrt{3} m-3=\sqrt{12} \\\\\sqrt{3} m=\sqrt{12} +3\\\\\sqrt{3}m=\sqrt{4.3} +3\\\\\sqrt{3}m=2\sqrt{3} +3\\\\m=\frac{2\sqrt{3}+3}{\sqrt{3} } \\\\m=2+\sqrt{3}[/tex] ✓correcto
Explicación paso a paso:
Espero que te ayude :) ♫♫