Respuesta:
[tex] \sqrt{ \frac{14\pi + 2\pi}{2\pi - \pi} } = \sqrt{ \frac{16\pi}{\pi} } = \sqrt{16} = 4[/tex]
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Respuesta:
[tex] \sqrt{ \frac{14\pi + 2\pi}{2\pi - \pi} } = \sqrt{ \frac{16\pi}{\pi} } = \sqrt{16} = 4[/tex]