seria asi la parte de arriba es x
hallamos x
[tex] {13}^{2} - {5}^{2} = {x}^{2} \\ 169 - 25 = {x}^{2} \\ 144 = {x}^{2} \\ \sqrt{144} = x \\ 12 = x[/tex]
hallamos el perimetro:
[tex]5 + 12 + 5 + 12 = x \\ 34 = x[/tex]
el perimetro es 34
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
seria asi la parte de arriba es x
hallamos x
[tex] {13}^{2} - {5}^{2} = {x}^{2} \\ 169 - 25 = {x}^{2} \\ 144 = {x}^{2} \\ \sqrt{144} = x \\ 12 = x[/tex]
hallamos el perimetro:
[tex]5 + 12 + 5 + 12 = x \\ 34 = x[/tex]
el perimetro es 34