Question

AYUDA POR FAVORR
Necesito buscar el valor numérico

Answer 1

Respuesta:

F) 13/12

G) - 13/8

H) 13/10

Explicación paso a paso:

F)

[tex] \frac{12c - a}{2b} - \frac{16n - a}{m} + \frac{1}{a} \\ = \frac{12(3) - 1}{2(2)} - \frac{16( \frac{1}{3} ) - 1}{ \frac{1}{2} } + \frac{1}{1} \\ = \frac{36 - 1}{4} - \frac{ \frac{16}{3} - 1 }{ \frac{1}{2} } + 1 \\ = \frac{35}{4} - \frac{ \frac{13}{3} }{ \frac{1}{2} } + 1 \\ = \frac{35}{4} - \frac{26}{3} + 1 \\ = \frac{105 - 104}{12} + 1 \\ = \frac{1}{12} + 1 \\ = \frac{13}{12} [/tex]

G)

[tex] \frac{ {a}^{2} }{3} - \frac{ {b}^{2} }{2} + \frac{ {m}^{2} }{6} \\ = \frac{ {1}^{2} }{3} - \frac{ {2}^{2} }{2} + \frac{ { \frac{1}{2} }^{2} }{6} \\ = \frac{1}{3} - \frac{4}{2} + \frac{ \frac{1}{4} }{6} \\ = \frac{2 - 12}{6} + \frac{1}{24} \\ = - \frac{10}{6} + \frac{1}{24} \\ = - \frac{13}{8} [/tex]

H)

[tex] \frac{3}{5} c - \frac{1}{2} b + 2p \\ = \frac{3}{5} \times 3 - \frac{1}{2} \times 2 + 2( \frac{1}{4} ) \\ = \frac{9}{5} - \frac{2}{2} + \frac{2}{4} \\ = \frac{18 - 10}{10} + \frac{2}{4} \\ = \frac{8}{10} + \frac{2}{4} \\ = \frac{32 + 20}{40} \\ = \frac{52}{40} \\ = \frac{13}{10} [/tex]