ayuda por favor jeyehwhuw.... Question from @frinerendon3

frinerendon3 @frinerendon3

August 2023 1 10 Report

ayuda por favor jeyehwhuw

Min0607

Verified answer

Respuesta:

Pasamos 0,9% a g/L

9g/L

Reemplazamos

[9g/L /58g] x 2 x 100

=310mOsmol/g

2 votes Thanks 1

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