Respuesta:
ojala y te sirva
Explicación paso a paso:
[tex] \frac{lim}{x > x} = \frac{5x - 20}{ {x}^{2} - 7x + 12} = \frac{5(x - 4)}{(x - 3)(x - 4)} = \frac{5}{x - 3} [/tex]
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Verified answer
Respuesta:
ojala y te sirva
Explicación paso a paso:
[tex] \frac{lim}{x > x} = \frac{5x - 20}{ {x}^{2} - 7x + 12} = \frac{5(x - 4)}{(x - 3)(x - 4)} = \frac{5}{x - 3} [/tex]