Question

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Answer 1

Respuesta:

de que se trata

Explicación paso a paso:

explica ggggg

Answer 2

Respuesta:

Explicación paso a paso:

09.

[tex]x^{2} +3x+7=0[/tex]

Por la fórmula general:

[tex]a = 1 ; b = 3 ; c = 7.[/tex]

[tex]x = \frac{-b\frac{+}{} \sqrt{b^{2}-4ac } }{2a} = \frac{-3\frac{+}{} \sqrt{3^{2} -4(1)(7)} }{2(1)} =\frac{-3\frac{+}{}\sqrt{9-28} }{2}[/tex]

[tex]x = \frac{-3\frac{+}{}\sqrt{-19} }{2}[/tex]

[tex]a = \frac{-3+\sqrt{-19} }{2}[/tex]       ;      [tex]b = \frac{-3-\sqrt{-19} }{2}[/tex]

[tex]a^{2} + b^{2} =(\frac{-3+\sqrt{-19} }{2} )^{2} + (\frac{-3-\sqrt{-19} }{2} )^{2}[/tex]

            [tex]= \frac{(-3)^{2}+2(-3)(\sqrt{-19} )+(\sqrt{-19} )^{2} }{4} + \frac{(-3)^{2}-2(-3)(\sqrt{-19} )+(\sqrt{-19} )^{2} }{4}[/tex]

            [tex]= \frac{9-6\sqrt{-19}-19+9+6\sqrt{-19} -19 }{4} = \frac{18-38}{4} = \frac{-20}{4}[/tex]

             [tex]= -5[/tex]

RESPUESTA:

       [tex]-5[/tex]

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10.

Raíces:

[tex]x_{1} = \sqrt{3} +\sqrt{2}[/tex]       ;        [tex]x_{2} = \sqrt{3} -\sqrt{2}[/tex]

[tex]Ecuacion:[/tex]

  [tex]x^{2} -(x_{1} +x_{2} )x + (x_{1}*x_{2} )=0[/tex]

[tex]x^{2} -(\sqrt{3} +\sqrt{2} +\sqrt{3} -\sqrt{2} )x+ [(\sqrt{3} +\sqrt{2} )*(\sqrt{3} -\sqrt{2}) =0[/tex]

[tex]x^{2} -2\sqrt{3} x + [ (\sqrt{3} )^{2} -(\sqrt{2} )^{2} ] =0[/tex]

[tex]x^{2} -2\sqrt{3} x+ (3-2) = 0[/tex]

RESPUESTA:

   [tex]x^{2} -2\sqrt{3} x+1 = 0[/tex]