Question

Ayuda plis a todos es urgente

1:. (3x-5y)(3x-5y)=


2: (2a³-8b⁴)(2a³+8b⁴)=

Answer 1

Verified answer

Respuesta:

1:. (3x-5y)(3x-5y)= [tex]\left(3x-5y\right)^2[/tex]

2: (2a³-8b⁴)(2a³+8b⁴)= [tex]4a^6-64b^8[/tex]

3⁚(3a²)(4a²)(-5a⁴)= [tex]-60a^8[/tex]

4⁚2x³(-3x²-3y⁴+6x²+9y⁴)= [tex]2x^3\left(3x^2+6y^4\right)[/tex]

5⁚(3x⁵)(-0.25x⁴)(-1/2x³)(1 2/3x²)= [tex]=\frac{3.75x^8}{6}[/tex]

Answer 2

Respuesta:

1)9x^2-30xy+25y^2

2)4a^6-64b^8

(el "^2" significa al cuadrado)

(el "^" significa potenciado a la)