Respuesta:
En el Paso a Paso
Explicación paso a paso:
a.- [tex](-2.34)^{0} = 1[/tex] (Todo numero elevado a la "0"da 1)
b.- [tex](\frac{5}{7} )^{0} = 1[/tex]
c.- [tex](-\pi )^{0} = 1[/tex]
d.- [tex]5^{3}. 5^{4} = 5^{3+4} = 5^{7}[/tex]
e.- [tex]\sqrt[3]{7^{2} } . \sqrt[3]{7^{4} } = 7^{\frac{2}{3} } . 7^{\frac{4}{3} }= 7^{\frac{2+4}{3} } = 7^{\frac{6}{3} } = 7^{2} = 49[/tex]
f.- [tex](\frac{-3}{5})^{3} . (\frac{-3}{5} )^{2} = (\frac{-3}{5})^{3+2} = (\frac{-3}{5})^{5} = \frac{-243}{3125}[/tex]
g.- [tex](0,123)^{3} . (7)^{3} = 0,63[/tex]
h.- [tex](\frac{2}{5})^{4} . (\frac{3}{5} )^{4} = \frac{16}{625} . \frac{81}{625} =\frac{1296}{390625}[/tex]
i.- [tex](-2)^{2} . (-2)^{2} = (-2)^{2+2} = (-2)^{4} = 16[/tex]
j.- [tex](\frac{3}{5} )^{4} / (\frac{5}{3} )^{3} = ( \frac{81}{625})/ ( \frac{125}{9})=\frac{81 . 9}{625 . 125} = \frac{729}{78125}[/tex]
k.- [tex]\frac{\sqrt{2}^{5} }{\sqrt{2}^{3} } = \frac{2^{\frac{5}{2} } }{2^{\frac{3}{2} } } = 2^{5/2 -3/2} = 2^{2/2} = 2^{1} =2[/tex]
l.- [tex]\frac{(-5)^{7} }{(-5)^{6} } = (-5) ^{7-6} = (-5)^{1} =-5[/tex]
m.- [tex]\sqrt[4]{6^{1} } = (6)^{\frac{1}{4} } = (6)^{0,25} = 1,56[/tex]
n.- [tex](\frac{5}{3} )^{2} = \frac{5.5}{3.3} =\frac{25}{9}[/tex]
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Verified answer
Respuesta:
En el Paso a Paso
Explicación paso a paso:
a.- [tex](-2.34)^{0} = 1[/tex] (Todo numero elevado a la "0"da 1)
b.- [tex](\frac{5}{7} )^{0} = 1[/tex]
c.- [tex](-\pi )^{0} = 1[/tex]
d.- [tex]5^{3}. 5^{4} = 5^{3+4} = 5^{7}[/tex]
e.- [tex]\sqrt[3]{7^{2} } . \sqrt[3]{7^{4} } = 7^{\frac{2}{3} } . 7^{\frac{4}{3} }= 7^{\frac{2+4}{3} } = 7^{\frac{6}{3} } = 7^{2} = 49[/tex]
f.- [tex](\frac{-3}{5})^{3} . (\frac{-3}{5} )^{2} = (\frac{-3}{5})^{3+2} = (\frac{-3}{5})^{5} = \frac{-243}{3125}[/tex]
g.- [tex](0,123)^{3} . (7)^{3} = 0,63[/tex]
h.- [tex](\frac{2}{5})^{4} . (\frac{3}{5} )^{4} = \frac{16}{625} . \frac{81}{625} =\frac{1296}{390625}[/tex]
i.- [tex](-2)^{2} . (-2)^{2} = (-2)^{2+2} = (-2)^{4} = 16[/tex]
j.- [tex](\frac{3}{5} )^{4} / (\frac{5}{3} )^{3} = ( \frac{81}{625})/ ( \frac{125}{9})=\frac{81 . 9}{625 . 125} = \frac{729}{78125}[/tex]
k.- [tex]\frac{\sqrt{2}^{5} }{\sqrt{2}^{3} } = \frac{2^{\frac{5}{2} } }{2^{\frac{3}{2} } } = 2^{5/2 -3/2} = 2^{2/2} = 2^{1} =2[/tex]
l.- [tex]\frac{(-5)^{7} }{(-5)^{6} } = (-5) ^{7-6} = (-5)^{1} =-5[/tex]
m.- [tex]\sqrt[4]{6^{1} } = (6)^{\frac{1}{4} } = (6)^{0,25} = 1,56[/tex]
n.- [tex](\frac{5}{3} )^{2} = \frac{5.5}{3.3} =\frac{25}{9}[/tex]