Respuesta:
1 como de helado
V=Vc+Vc
v=(1/3hπr²)+{(4/3 πr³)/2}
V=(1/3×12×π×4²)+{(4/3 ×π×4³)/2}
V=(1/3×12×π×16)+{(4/3 ×π×64)/2}
V=(1/3×192×π)+{( 85,3×π)/2}
V=64π+267,98/2
V=201,06 +133,99
V=335,05 cm³
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Respuesta:
1 como de helado
V=Vc+Vc
v=(1/3hπr²)+{(4/3 πr³)/2}
V=(1/3×12×π×4²)+{(4/3 ×π×4³)/2}
V=(1/3×12×π×16)+{(4/3 ×π×64)/2}
V=(1/3×192×π)+{( 85,3×π)/2}
V=64π+267,98/2
V=201,06 +133,99
V=335,05 cm³