Respuesta:
ayuda, lo necesito ahora <,3.
Explicación paso a paso:
[tex]\frac{5x+2y}{3}=1\\\frac{3\left(5x+2y\right)}{3}=1\cdot \:3\\5x+2y=3\\5x+2y-2y=3-2y\\\frac{5x}{5}=\frac{3}{5}-\frac{2y}{5}\\x=\frac{3-2y}{5}[/tex]
[tex]\frac{2x+y}{2}=2\\\frac{2\left(2x+y\right)}{2}=2\cdot \:2\\2x+y=4\\2x+y-y=4-y\\2x=4-y\\\frac{2x}{2}=\frac{4}{2}-\frac{y}{2}\\x=\frac{4-y}{2}[/tex]
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Respuesta:
ayuda, lo necesito ahora <,3.
Explicación paso a paso:
[tex]\frac{5x+2y}{3}=1\\\frac{3\left(5x+2y\right)}{3}=1\cdot \:3\\5x+2y=3\\5x+2y-2y=3-2y\\\frac{5x}{5}=\frac{3}{5}-\frac{2y}{5}\\x=\frac{3-2y}{5}[/tex]
[tex]\frac{2x+y}{2}=2\\\frac{2\left(2x+y\right)}{2}=2\cdot \:2\\2x+y=4\\2x+y-y=4-y\\2x=4-y\\\frac{2x}{2}=\frac{4}{2}-\frac{y}{2}\\x=\frac{4-y}{2}[/tex]